Worked Example — Titration Calculation
Part of Titrations (HT) — GCSE Chemistry
This worked example covers Worked Example — Titration Calculation within Titrations (HT) for GCSE Chemistry. Revise Titrations (HT) in Quantitative Chemistry for GCSE Chemistry with 22 exam-style questions and 20 flashcards. This topic appears regularly enough that it should still be part of a steady revision cycle. It is section 5 of 13 in this topic. Treat this as a marking guide for what examiners are looking for, not just a fact list.
Topic position
Section 5 of 13
Practice
22 questions
Recall
20 flashcards
🧮 Worked Example — Titration Calculation
Question: 25.0 cm³ of sodium hydroxide solution was titrated with 0.100 mol/dm³ hydrochloric acid. The mean titre was 22.50 cm³. Calculate the concentration of NaOH.
Equation: NaOH + HCl → NaCl + H₂O
n = c × V (where V is in dm³)
n = 0.100 × (22.50 ÷ 1000)
n = 0.100 × 0.02250
n = 0.00225 mol HCl
NaOH : HCl = 1 : 1
So moles NaOH = moles HCl = 0.00225 mol
c = n ÷ V
c = 0.00225 ÷ (25.0 ÷ 1000)
c = 0.00225 ÷ 0.0250
c = 0.0900 mol/dm³