Worked Example — Titration Calculation

Part of Titrations (HT) · Section 5 of 14

Worked ExampleUnit: Quantitative ChemistryGCSE

This worked example covers Worked Example — Titration Calculation within Titrations (HT) for GCSE Chemistry. Revise Titrations (HT) in Quantitative Chemistry for GCSE Chemistry with 22 exam-style questions and 20 flashcards. This topic shows up very often in GCSE exams, so students should be able to explain it clearly, not just recognise the term. It is section 5 of 14 in this topic. Treat this as a marking guide for what examiners are looking for, not just a fact list.

🧮 Worked Example — Titration Calculation

Question: 25.0 cm³ of sodium hydroxide solution was titrated with 0.100 mol/dm³ hydrochloric acid. The mean titre was 22.50 cm³. Calculate the concentration of NaOH.
Equation: NaOH + HCl → NaCl + H₂O

Step 1: Calculate moles of HCl used
n = c × V (where V is in dm³)
n = 0.100 × (22.50 ÷ 1000)
n = 0.100 × 0.02250
n = 0.00225 mol HCl
Step 2: Use the equation ratio
NaOH : HCl = 1 : 1
So moles NaOH = moles HCl = 0.00225 mol
Step 3: Calculate concentration of NaOH
c = n ÷ V
c = 0.00225 ÷ (25.0 ÷ 1000)
c = 0.00225 ÷ 0.0250
c = 0.0900 mol/dm³

Practice questions for Titrations (HT)

What is the purpose of a titration?

  • A. To find the unknown concentration of a solution
  • B. To measure the temperature change of a reaction
  • C. To separate a mixture into its components
  • D. To identify the gas produced in a reaction
1 markfoundation

Explain why the burette should be rinsed with the acid solution before filling it for a titration.

2 marksstandard

Quick recall flashcards

What is a titration?
A technique to find an unknown concentration by adding a solution of known concentration until the reaction is complete You measure exactly how much was added
What are concordant results?
Titration results within 0.10 cm³ of each other These are the reliable results used to calculate the mean

22 questions on Titrations (HT) — practise free

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