Exam Tips for Work Done and Energy Transfer
Part of Work Done & Energy Transfer — GCSE Physics
This exam tips covers Exam Tips for Work Done and Energy Transfer within Work Done & Energy Transfer for GCSE Physics. Revise Work Done & Energy Transfer in Forces for GCSE Physics with 13 exam-style questions and 6 flashcards. This is a high-frequency topic, so it is worth revising until the explanation feels precise and repeatable. It is section 12 of 13 in this topic. Treat this as a marking guide for what examiners are looking for, not just a fact list.
Topic position
Section 12 of 13
Practice
13 questions
Recall
6 flashcards
💡 Exam Tips for Work Done and Energy Transfer
🎯 Common Question Types:
- Calculate work done given force and distance (1-2 marks)
- Calculate power from work done and time (1-2 marks)
- Explain what happens to energy when work is done against friction (2 marks)
- Elastic PE calculations using Ep = ½ke² (higher, 2-3 marks)
📝 Key Command Words:
- Calculate: W = Fs — show equation, substitution, and unit (J)
- Explain: State the energy transfer — what store gains, what loses
- Describe: State that work done against friction → thermal energy
- State: "Work done = energy transferred" is often a free 1 mark
⚠️ Common Mistakes to Avoid:
- Using mass instead of weight (force) in W = Fs when lifting objects
- Confusing work done (J) with power (W) — they have different units
- Forgetting distance must be in the direction of the force
- Thinking stationary objects have "work done on them" — no movement = no work
Quick Check: An electric motor transfers 12,000 J of energy in 2 minutes. What is its power output?
P = W ÷ t = 12,000 ÷ 120 = 100 W. Note: convert minutes to seconds first! 2 minutes = 120 seconds.
Quick Check: Explain why a person carrying a heavy bag along a flat corridor does no work on the bag's weight.
The lifting force on the bag acts upward, but the displacement is horizontal. The force is perpendicular to the direction of motion, so no work is done by the lifting force. Work done = F × distance in direction of force = F × 0 (no vertical movement) = 0 J.