Solve: 3x + 7 < 19
Step 1 Subtract 7 from both sides
3x + 7 - 7 < 19 - 7
3x < 12
Step 2 Divide both sides by 3
3x ÷ 3 < 12 ÷ 3
x < 4
Step 3 Check with x = 3
3(3) + 7 = 16, and 16 < 19 ✓
This study notes covers Worked Example 1: Simple Inequality within Linear Inequalities for GCSE Mathematics. Revise Linear Inequalities in Algebra for GCSE Mathematics with 14 exam-style questions and 11 flashcards. This is a high-frequency topic, so it is worth revising until the explanation feels precise and repeatable. It is section 4 of 8 in this topic. Use this study notes to connect the idea to the wider topic before moving on to questions and flashcards.
Practice questions for Linear Inequalities
Which of the following correctly describes how to represent x > 3 on a number line?
When solving an inequality, the direction of the inequality sign must reverse if you multiply or divide both sides by a negative number. Explain why this rule is necessary. You may use an example to support your explanation.