We read the actual downloaded question papers and mark schemes for every AQA Biology Paper 2 Higher Tier sitting we have available. The June 2020 paper carries a printed date of Monday 1 June 2020 on its own cover, and the June 2021 paper is filed on AQA's server under a November folder but its own mark scheme cover and watermark both confirm June 2021 as the real sitting. Below is what each question type has actually asked, what the real graphs, family trees and experimental setups showed, and a complete worked answer written to the mark scheme's top level for the extended response questions. This is the closest you can get to seeing exactly what a full mark answer looks like without a real exam paper in front of you.
Questions © AQA, quoted for analysis. Diagrams, tables, graphs and family trees described in our own words, not reproduced. Mark scheme content translated into plain English, not copied. PrepWise is independent and not endorsed by AQA.
Two of the four sittings we analysed built a 6-mark question around exactly this structure: a picture of dead material decaying (a compost heap or fallen leaves), asking you to trace both the breakdown by microorganisms and the reuse of the released substances by a living plant. The mark scheme rewards scientifically accurate, detailed points over a long list of vague ones.
The real Q04 (6 marks) shows a compost heap with alternating layers of dead plant material and thin layers of soil, and wants a full account of how carbon and nitrogen compounds cycle from the dead plants back into living plants via the microorganisms in the soil.
A diagram of a compost heap, drawn in cross section, showing alternating layers of dead plant material and thin layers of soil built up on top of each other.
Microorganisms in the soil layers, bacteria and fungi, digest the dead plant material using enzymes, breaking down large molecules such as proteins and carbohydrates into smaller soluble molecules. These microorganisms then respire, which releases carbon dioxide as a waste product into the air around the compost heap.
That carbon dioxide diffuses out of the compost heap and into the air, where it can be taken in through the stomata of a living plant's leaves. Inside the leaf, the carbon dioxide is used in photosynthesis, combining with water to make glucose, which the plant can convert into starch or cellulose for its cell walls.
The digestion of proteins in the dead plant material also releases nitrogen compounds into the soil as mineral ions such as nitrate. These nitrate ions are absorbed by the roots of a living plant, using active transport since the concentration of nitrate is often higher inside the root hair cells than in the soil.
Once inside the plant, the nitrate ions are used to make amino acids, which are then built into proteins the plant needs for growth, and nitrate is also needed to make chlorophyll and DNA. This completes the recycling of nitrogen from the dead plant material back into a new generation of living plant tissue.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise decomposition and nutrient cycling questionsNo diagram accompanies this variant; the question states directly that dead leaves contain carbon compounds and nitrogen compounds and asks how both are recycled and used by living trees.
The dead leaves are broken down by decomposers, bacteria and fungi, which digest the large carbon and nitrogen compounds in the leaf tissue using enzymes, turning them into smaller, soluble substances. As the decomposers respire to release energy from this digested material, they produce carbon dioxide as a waste product, which is released into the air.
This carbon dioxide is taken in by nearby living trees through the stomata on their leaves, by diffusion, and is used in photosynthesis to produce glucose. The tree can then convert this glucose into starch for storage or into cellulose to build new cell walls as it grows.
The decay of proteins in the dead leaves also releases nitrate ions into the soil. These nitrate ions are absorbed into the tree's roots by active transport, since the nitrate concentration is often lower in the soil than inside the root hair cells.
The nitrate is then used by the tree to build amino acids, which are combined to make new proteins for growth and repair, and nitrate is also essential for producing chlorophyll and DNA in new cells. In this way, both the carbon and the nitrogen originally locked up in the dead leaves are returned to the living tree.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise decomposition and nutrient cycling questionsThe topic changes by sitting — the mark scheme never does. Learn this once, then open your question above for that sitting’s sources and a full worked answer.
Which organisms are the main decomposers?
This question always splits into a carbon half and a nitrogen half, and marks are lost for only doing one properly. Practise naming the exact gas, ion and process at every step.
Practise decomposition and nutrient cycling questionsEvery sitting we analysed with a plant hormone question builds it around a real shoot-tip or agar-block experiment, then asks you to interpret what the data show about auxin's role in phototropism. The specific numbers and hypothesis change, but the skill tested is always reading experimental evidence, not reciting a textbook definition.
The real Q03.4 (3 marks) shows a seedling growing towards a lamp with the shoot curved, side P nearest the lamp and side Q furthest away, and wants an explanation of why side Q grew more than side P.
A diagram of a lamp positioned to one side of a growing seedling, with the shoot shown curving towards the lamp. Side P is labelled as the side of the shoot nearest the lamp, and side Q as the side furthest from the lamp.
Side Q, the side furthest from the lamp, received less light than side P, so more auxin built up on side Q because auxin moves towards the shaded side of the shoot. This higher concentration of auxin on side Q caused the cells there to elongate more than the cells on side P.
Because side Q grew more than side P, the shoot bent towards the lamp, since the shorter, less-elongated side P effectively pulled that side of the shoot towards the light source.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise plant hormone and phototropism questionsThe real Q09.5 (3 marks) shows four shoot tips placed on agar blocks under different lighting conditions, with numbers showing the mass of auxin that diffused into each block, and wants you to pick out which numbers support the stated hypothesis.
Four separate shoot-tip experiments (labelled D, E, F and G) each with a shoot tip placed on a small block of agar jelly. Two are kept in the dark and two receive one-sided light, with numbers given under each block showing the mass of auxin, in arbitrary units, that diffused into that block, split by side for the blocks that were cut in half with a thin strip of glass down the middle.
| Experiment | Condition | Auxin diffused — left half, units | Auxin diffused — right half, units |
|---|---|---|---|
| D | Kept in the dark (block not split) | 25.3 | not split |
| E | Kept in the dark (split by glass) | 12.5 | 12.4 |
| F | One-sided light from the right (split by glass) | 17.2 | 7.8 |
| G | One-sided light from the right (split by glass) | 12.6 | 12.6 |
In experiment E, which was kept in the dark with a glass barrier splitting the agar block into two halves, the mass of auxin was almost equal in both halves (12.5 and 12.4 units), showing that without one-sided light, auxin diffuses evenly to both sides of the shoot.
In experiment F, which had one-sided light and the same glass barrier, the mass of auxin was much higher on the side furthest from the light (17.2 units) than on the side nearest the light (7.8 units). This uneven split only appeared when light was one sided, which supports the hypothesis that light causes auxin to move away from the light towards the shaded side.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise plant hormone and phototropism questionsThe topic changes by sitting — the mark scheme never does. Learn this once, then open your question above for that sitting’s sources and a full worked answer.
When a plant shoot is lit from one side, where does auxin accumulate?
This question is always about reading real numbers from an auxin experiment, not reciting the theory from memory. Practise picking out the exact comparison the data shows.
Practise plant hormone and phototropism questionsBoth sittings we analysed with a temperature regulation question isolate one specific mechanism, either why drinking something cold changes internal body temperature, or why dilating blood vessels helps to cool the body down, and ask for a mechanistic chain rather than a one-line fact.
The real Q03.3 (2 marks) follows a graph showing a person's internal body temperature dipping sharply after drinking 500cm³ of ice-cold water, and wants the physical explanation for why that measured drop near the brain happens.
A line graph of internal body temperature in degrees Celsius over 70 minutes, showing a steady 37.4 degrees Celsius baseline that dips sharply to around 36.8 degrees Celsius shortly after the point marked 'drinks ice-cold water', then rises back to baseline.
The blood is cooled as it passes close to the ice-cold water in the stomach and mouth, since heat is transferred from the warmer blood into the colder water. This cooled blood then circulates around the body and flows to the brain, lowering the temperature measured there.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise temperature regulation questionsThe real Q08.4 (3 marks) is about an echidna waking from hibernation with a body temperature over 30 degrees Celsius, and wants an explanation of how dilating skin blood vessels specifically brings that temperature back down.
The stem states the echidna's body temperature rises above 30 degrees Celsius each time it wakes from hibernation, and that it can dilate or constrict blood vessels in its skin, without an accompanying diagram.
More blood flows nearer to the surface of the skin when the blood vessels there dilate, because the wider vessels allow a greater volume of blood to pass close to the skin's surface. This means more heat is able to transfer from the blood to the surrounding air, since heat can escape more easily the closer the blood is to the surface.
As heat is lost from this blood to the environment, the blood itself becomes cooler, and this cooler blood then circulates back around the echidna's body, lowering its overall body temperature.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise temperature regulation questionsThe topic changes by sitting — the mark scheme never does. Learn this once, then open your question above for that sitting’s sources and a full worked answer.
What is the normal core body temperature in humans?
This question always wants a short, specific mechanism chain rather than a general homeostasis fact. Practise linking each step clearly.
Practise temperature regulation questionsBoth sittings we analysed test the same underlying skill, negative feedback, but from two different angles: one gives you a real blood glucose graph and asks for insulin's specific effect, the other gives a generic negative feedback diagram with two hormones and asks you to explain the whole loop using the diagram's own labels.
The real Q03.2 (3 marks) follows a graph of blood glucose concentration rising sharply after a meal and then falling back to baseline within about two hours, and wants the effect of insulin plus the mechanism by which it lowers glucose.
A line graph of blood glucose concentration in mmol per cubic decimetre over 4 hours, starting around 4.4, rising to a peak of about 6.0 roughly 90 minutes after a meal is eaten, then falling back down to around 4.4 by 2.5 hours and staying level.
A high concentration of insulin lowers blood glucose concentration. This happens because insulin causes glucose to be taken into cells, and it also causes the liver and muscles to convert excess glucose into glycogen for storage.
These processes are carried out by cells throughout the body, but the liver and muscle cells in particular store the excess glucose as glycogen, which explains why blood glucose concentration falls back towards its normal level within around two hours of the meal.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise glucose regulation and negative feedback questionsThe real Q05.1 (3 marks) shows a generic negative feedback diagram with an ideal concentration of a substance Q, and arrows showing hormone A released if Q rises too high and hormone B released if Q falls too low, and wants the whole loop explained using the diagram's own labels.
A generic negative feedback diagram with a central box showing 'ideal concentration of substance Q', with an arrow labelled 'increase of substance Q' leading up to a box 'concentration of substance Q too high', which has an arrow labelled 'hormone A' pointing back down to the ideal box. A mirrored arrow labelled 'decrease of substance Q' leads down to a box 'concentration of substance Q too low', which has an arrow labelled 'hormone B' pointing back up to the ideal box.
If the concentration of substance Q becomes too high, hormone A is released and used to bring the concentration back down towards the ideal level.
If the concentration of substance Q becomes too low, hormone B is released and used to bring the concentration back up towards the ideal level.
In both cases the released hormone acts to bring substance Q's concentration back to its ideal, normal level, which is the defining feature of a negative feedback system.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise glucose regulation and negative feedback questionsThe topic changes by sitting — the mark scheme never does. Learn this once, then open your question above for that sitting’s sources and a full worked answer.
Which organ monitors blood glucose concentration and secretes insulin and glucagon?
Negative feedback questions always want both directions of the loop and the specific mechanism, not just 'a hormone fixes it'. Practise stating the full chain.
Practise glucose regulation and negative feedback questionsThis is one of the most reliable questions on the whole paper. All four sittings we analysed include a real family pedigree or genetics scenario followed by a Punnett square question worth 4 or 5 marks, always rewarding the same sequence: correct gametes, correct offspring genotypes, correct phenotypes, and a correct final probability.
The real Q05.4 (5 marks) gives a family pedigree tree showing Dupuytren's, a dominant condition, tracked across three generations, with person 7 identified as affected and married to unaffected person 8, and wants a full Punnett square for their next child.
A family pedigree tree spanning three generations, using filled and unfilled squares (males) and circles (females) to show who has Dupuytren's, with person 7 shown as an affected male married to person 8, an unaffected female, and their existing three children shown below them.
Person 7 has Dupuytren's, caused by the dominant allele D, and from earlier working in the question is known to be heterozygous, Dd. Person 8 does not have Dupuytren's and so is homozygous recessive, dd. Person 7's gametes are therefore D and d, and person 8's gametes are both d.
Drawing a Punnett square with person 7's gametes D and d along the top and person 8's gametes d and d down the side gives four offspring genotypes: Dd, Dd, dd and dd.
The genotypes Dd have Dupuytren's, since D is dominant, while the genotypes dd do not have Dupuytren's. This means two of the four possible offspring, or half, would have Dupuytren's.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise genetic inheritance and Punnett square questionsThe real Q08.3 (5 marks) gives a family pedigree for sickle cell anaemia, showing person 8 as unaffected (homozygous normal) and person 9 as a carrier with sickle cell trait (heterozygous), and asks for the probability their child is BOTH female AND has sickle cell trait.
A family pedigree tree for sickle cell anaemia across three generations, using a colour/shading key to distinguish unaffected individuals, those with sickle cell trait (heterozygous carriers) and those with sickle cell anaemia (homozygous for the mutated allele), with person 8, an unaffected male, married to person 9, a female with sickle cell trait.
Person 8 does not have sickle cell anaemia or trait, so is homozygous for the normal allele, HAHA, giving gametes of HA and HA. Person 9 has sickle cell trait, meaning she is heterozygous, HAHS, giving gametes of HA and HS.
Crossing person 8's gametes (HA and HA) with person 9's gametes (HA and HS) in a Punnett square gives four offspring genotypes: HAHA, HAHA, HAHS and HAHS.
The genotypes HAHA do not have sickle cell anaemia or trait, while the genotypes HAHS have sickle cell trait but are generally healthy. Since sex is inherited separately and independently, with an equal 1 in 2 chance of the child being female, the combined probability of a child being both female AND having sickle cell trait is 1/2 (probability of trait) multiplied by 1/2 (probability of female), which equals 1/4.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise genetic inheritance and Punnett square questionsThe real Q05.2 (4 marks) gives a family pedigree for maple syrup urine disease (MSUD), a recessive condition, with persons 7 and 8 both shown as unaffected carriers based on their children, and wants the probability their next child has the condition.
A family pedigree tree for maple syrup urine disease across three generations, with persons 7 and 8 shown as an unaffected couple whose existing children include at least one child with MSUD, alongside unaffected children.
Since persons 7 and 8 are both unaffected but have already had a child with MSUD, a recessive condition, they must both be heterozygous carriers, Nn, giving gametes of N and n from each parent.
Crossing the gametes N and n from person 7 with N and n from person 8 in a Punnett square gives four offspring genotypes: NN, Nn, Nn and nn.
The genotype nn is the only one that has MSUD, since the condition is recessive, so one out of the four possible offspring, or a quarter, would be expected to have MSUD.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise genetic inheritance and Punnett square questionsThe real Q07.4 (3 marks) states that a woman who does not produce FSH inherited a faulty recessive allele from each of her two parents, who themselves both produce FSH, and asks for a Punnett square showing how two unaffected parents could still have this outcome.
The stem explains that usually both males and females produce FSH, that the woman inherited a faulty gene for FSH production from each of her parents, and that both of her parents do produce FSH themselves, with no accompanying pedigree diagram for this specific variant.
Since the woman does not produce FSH, and this is recessive, she must be homozygous recessive, hh. As stated in the question, she inherited one faulty allele from each parent, so both of her parents must carry at least one copy of the h allele, meaning both are heterozygous, Hh, giving gametes of H and h from each parent.
Crossing gametes H and h from one parent with H and h from the other parent in a Punnett square gives four offspring genotype combinations: HH, Hh, Hh and hh.
The genotypes HH and Hh both produce FSH, since H is dominant, while the genotype hh does not produce FSH. This shows that even though both parents themselves produce FSH, there is a 1 in 4 chance of a child not producing FSH, exactly matching the woman's own situation described in the question.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise genetic inheritance and Punnett square questionsThe topic changes by sitting — the mark scheme never does. Learn this once, then open your question above for that sitting’s sources and a full worked answer.
What is the term for an allele that is always expressed when present?
Punnett square questions always reward the full chain: gametes, genotypes, phenotypes, then probability. Practise every step, not just the final fraction.
Practise genetic inheritance and Punnett square questionsTwo of the four sittings we analysed build a high-tariff evolution question, one following a single population through a specific mutation and natural selection (birds evolving UV vision), the other asking more broadly how two different strands of evidence, fossils and genetics, have together developed our understanding of evolution since Darwin.
The real Q06.5 (6 marks) states that some birds' eyes contain cells that detect ultraviolet light, that UV light is reflected by some fruits and by the urine of small mammals, and wants the full natural selection story for how this trait spread through a bird population.
The stem states that the eyes of some birds contain cells that detect ultraviolet light, and that UV light is reflected by some fruits and by the urine of small mammals, with no accompanying diagram.
A random mutation occurred in the gene for a visual pigment in the retina of a bird, by chance, causing that bird's retina to produce a slightly different pigment able to detect a wider range of wavelengths of light, including ultraviolet.
Birds with this mutation could detect ultraviolet light, so they were more likely to see fruits that reflect UV light, and more likely to see the urine trails of small mammals, which also reflects UV light, helping them locate prey.
Because they could find more food, birds with the UV-detecting mutation were more likely to survive and reproduce than birds without the mutation, outcompeting them for the same limited food sources.
These surviving birds passed the mutated allele on to their offspring, and over many generations, more and more birds in the population inherited the ability to detect UV light, until eventually most or all birds in that population had evolved this trait by natural selection.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise evolution and natural selection questionsThe real Q09 (6 marks) explicitly names two separate strands, fossil evidence and genetics, and requires both to be covered in detail for the top level, since a Level 3 answer specifically needs both parts addressed.
The stem states that a wide variety of species exists on Earth and that most scientists accept Darwin's theory of evolution by natural selection as the explanation for this, with no accompanying diagram.
Fossils give us direct evidence of organisms that lived in the past, showing how species have changed over time and providing evidence of species that have since become extinct. By comparing fossils of different ages, scientists can build evolutionary trees showing how organisms alive today are related to earlier species.
There are still gaps in the fossil record because the conditions needed for a fossil to form are rare, so not every organism that has ever lived has left a trace. However, new fossil discoveries keep being made, and these help fill in some of the gaps, giving a clearer picture of exactly how and when different species diverged from one another.
Separately, our understanding of genetics has also developed. Mendel's breeding experiments with pea plants first suggested that characteristics are passed on as separate units, which we now know as genes or alleles, occurring in dominant and recessive forms. Later, scientists observed chromosome behaviour during cell division and found that it matched the pattern Mendel had already worked out mathematically. Eventually the structure of DNA was discovered, and the mechanism by which genes control protein production was worked out too.
This understanding of genetics explains where variation within a species comes from, since a mutation can change the structure of a gene. If that mutation gives an individual an advantageous characteristic, that individual is more likely to survive in its environment. Because it survives, it is also more likely to reproduce, and when it does, it passes on the advantageous allele to its offspring, so the allele becomes more common in the population over generations.
A real example of this is antibiotic resistance in bacteria. A random mutation can make a bacterium resistant to an antibiotic; when the population is exposed to that antibiotic, the resistant bacterium survives and reproduces while non-resistant bacteria are killed, so the resistance allele spreads through the population. More generally, if enough genetic change accumulates in a population over time, it can become so different from the original population that it can no longer successfully reproduce with it, which is how a new species can eventually arise.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise evolution and natural selection questionsThe topic changes by sitting — the mark scheme never does. Learn this once, then open your question above for that sitting’s sources and a full worked answer.
What is evolution?
This question either wants a full natural selection chain for one specific trait, or detailed coverage of every strand named in the question. Missing depth on one part caps your mark well below full marks.
Practise evolution and natural selection questionsThe reflex arc question always asks you to trace the full pathway from stimulus through to muscle response, naming each part of the nervous system in the correct order. Marks are lost for skipping a stage or naming the parts out of sequence.
The real Q06.2 (6 marks) gives a specific real-life scenario, a hand touching something hot and being pulled away, and wants the full nervous system pathway that coordinates that automatic, rapid response.
The stem describes a woman's hand accidentally touching a hot object and the hand being moved away rapidly, with no accompanying diagram.
A receptor in the skin of the woman's finger or hand detects the temperature change caused by touching the hot object, and this triggers an electrical impulse that passes along a sensory neurone towards the spinal cord.
At a synapse in the spinal cord, the impulse passes from the sensory neurone to a relay neurone. This happens because a chemical (a neurotransmitter) is released across the gap between the two neurones, triggering a new electrical impulse in the relay neurone.
The impulse then passes along the relay neurone, which is located entirely within the spinal cord, and across a second synapse to a motor neurone, again using a neurotransmitter to cross this gap.
The impulse travels along the motor neurone to a muscle in the woman's arm, which is the effector. The muscle contracts, pulling the hand away from the hot object rapidly, without the woman needing to consciously think about the action.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise reflex arc questionsThe topic changes by sitting — the mark scheme never does. Learn this once, then open your question above for that sitting’s sources and a full worked answer.
Which word best describes a reflex action?
This question always wants the full pathway named in the correct order, receptor to sensory neurone to synapse to relay neurone to synapse to motor neurone to effector. Missing a stage loses marks even if the general idea is right.
Practise reflex arc questionsAcross the 4 sittings we have full papers for, these are the topics with the most exam appearances and marks at stake on Paper 2.
Ecosystems, the carbon cycle and biodiversity as a standalone extended response topic (Unit 4 Ecology) in these four papers · The human nervous system and endocrine system as standalone extended response topics separate from the specific glucose/temperature examples covered · Selective breeding, genetic engineering and cloning as a standalone extended response topic in these four papers
These topics have not carried a full extended response question in the papers we analysed, but can still appear as shorter structured questions, so do not skip them entirely.
The context and data are described in our own words, not reproduced, and the worked answers are written entirely by us, aimed at the actual level descriptors of the real AQA mark schemes for each sitting. They are not copied from AQA's own exemplar materials, since that would breach copyright, but they are built to hit exactly what the real mark scheme rewarded that year. PrepWise is independent of AQA and not endorsed by them.
The Punnett square question returns in some form in every single sitting we analysed, and evolution, plant hormones, temperature regulation and glucose regulation all return regularly too. But you cannot rely on repeats alone, since the exact condition, numbers and context change every time even when the question type is similar. Use this page to see which TOPICS and QUESTION TYPES keep returning and make sure you know the underlying biology cold, whatever the exact wording turns out to be.
Yes, PrepWise is free during alpha. You can practise every topic on this page without paying anything right now.
Every topic on this page has practice questions waiting in the app, scored the way AQA actually marks them.
Start revising free