Quantitative ChemistryWorked Example

Concentration Worked Example

Part of Moles & CalculationsGCSE Chemistry

This worked example covers Concentration Worked Example within Moles & Calculations for GCSE Chemistry. Revise Moles & Calculations in Quantitative Chemistry for GCSE Chemistry with 22 exam-style questions and 20 flashcards. This is a high-frequency topic, so it is worth revising until the explanation feels precise and repeatable. It is section 14 of 17 in this topic. Treat this as a marking guide for what examiners are looking for, not just a fact list.

Topic position

Section 14 of 17

Practice

22 questions

Recall

20 flashcards

🧮 Concentration Worked Example

Concentration measures how many moles of solute are dissolved in 1 dm³ of solution:

c = n ÷ V     (concentration = moles ÷ volume in dm³)

Question: 0.25 mol of NaOH is dissolved in 500 cm³ of water. Calculate the concentration in mol/dm³.

Step 1: Convert volume to dm³
500 cm³ ÷ 1000 = 0.5 dm³
Step 2: Apply the formula
c = n ÷ V = 0.25 ÷ 0.5 = 0.5 mol/dm³

Answer: 0.5 mol/dm³

Always convert cm³ to dm³ first by dividing by 1000. Forgetting this step is the most common mistake in concentration calculations.

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Read this section alongside the surrounding pages in Moles & Calculations. That gives you the full topic sequence instead of a single isolated revision point.

Practice Questions for Moles & Calculations

One mole of any substance contains how many particles?

  • A. 6.02 × 10²³
  • B. 6.02 × 10²⁰
  • C. 3.01 × 10²³
  • D. 6.02 × 10¹⁸
1 markfoundation

Explain why the percentage yield of a reaction is never 100% in practice.

2 marksstandard

Quick Recall Flashcards

What is Avogadro's constant?
6.02 × 10²³ particles per mole This is the number of particles in one mole of any substance.
Define 'one mole'
The amount of substance containing 6.02 × 10²³ particles One mole of any element weighs exactly its Ar in grams

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