Geometry & MeasuresExam Tips

Invalid Conditions — Common Traps

Part of CongruenceGCSE Mathematics

This exam tips covers Invalid Conditions — Common Traps within Congruence for GCSE Mathematics. Revise Congruence in Geometry & Measures for GCSE Mathematics with 15 exam-style questions and 12 flashcards. This is a high-frequency topic, so it is worth revising until the explanation feels precise and repeatable. It is section 4 of 10 in this topic. Treat this as a marking guide for what examiners are looking for, not just a fact list.

Topic position

Section 4 of 10

Practice

15 questions

Recall

12 flashcards

Invalid Conditions — Common Traps

  • AAA (Angle-Angle-Angle) is NOT sufficient for congruence. Three equal angles gives similar triangles, but they could be any size.
  • SSA (or ASS) is NOT a valid congruence condition. Two sides and a non-included angle can produce two different triangles (the ambiguous case).
  • In SAS, the angle must be between the two sides — it is not enough for any angle to be equal.
  • RHS only works when you know there is a right angle — you cannot assume it.

Keep building this topic

Read this section alongside the surrounding pages in Congruence. That gives you the full topic sequence instead of a single isolated revision point.

Practice Questions for Congruence

Which of the following is NOT a valid congruence condition for triangles?

  • A. SSS (three sides equal)
  • B. SAS (two sides and the included angle equal)
  • C. AAA (three angles equal)
  • D. RHS (right angle, hypotenuse and one side equal)
1 markfoundation

When writing a congruence statement, such as triangle ABC ≅ triangle PQR, explain what it tells you about the sides and angles of the two triangles.

3 marksstandard

Quick Recall Flashcards

SAS Congruence Condition
Side-Angle-Side: Two sides and the INCLUDED angle (the angle between the two sides) are equal. The angle MUST be between the two sides — if it is not included, SAS does not apply.
SSS Congruence Condition
Side-Side-Side: All three pairs of corresponding sides are equal. If AB = DE, BC = EF, and AC = DF, then the triangles are congruent. Fixing three side lengths determines the triangle completely.

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