Particle ModelMemory Aid

Memory Aid

Part of Specific Latent HeatGCSE Physics

This memory aid covers Memory Aid within Specific Latent Heat for GCSE Physics. Revise Specific Latent Heat in Particle Model for GCSE Physics with 13 exam-style questions and 30 flashcards. This is a high-frequency topic, so it is worth revising until the explanation feels precise and repeatable. It is section 8 of 12 in this topic. Use it for quick recall, then test yourself straight afterwards so the memory aid becomes usable in an answer.

Topic position

Section 8 of 12

Practice

13 questions

Recall

30 flashcards

🧠 Memory Aid

Remembering the two types:

  • Fusion = Freezing/melting (solid-liquid boundary) — think "F for Floor" (the lower level)
  • Vaporisation = Very hot (liquid-gas boundary) — think "V for Very high energy"

The equation E = mL: Think "Enormous mass x Latent heat = Enormous energy." Or use the triangle: E on top, m bottom-left, L bottom-right. Cover what you want to find.

Why steam burns more: Steam at 100°C → skin → condenses → releases 2,260,000 J/kg (latent heat) PLUS cools down further. Boiling water only cools down — no latent heat released. So steam is the nastier one.

Keep building this topic

Read this section alongside the surrounding pages in Specific Latent Heat. That gives you the full topic sequence instead of a single isolated revision point.

Practice Questions for Specific Latent Heat

What is specific latent heat?

  • A. The energy needed to raise 1 kg of a substance by 1 °C
  • B. The energy needed to change the state of 1 kg of a substance without changing its temperature
  • C. The temperature at which a substance changes state
  • D. The rate of energy transfer during a state change
1 markfoundation

During a state change, energy is being supplied to a substance but the temperature does not change. Explain where this energy goes.

2 marksstandard

Quick Recall Flashcards

What is latent heat?
Energy needed to change state without changing temperature. 'Latent' = hidden.
Latent heat equation
E = mL

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