We read the real Higher Tier papers Edexcel has published for Chemistry Paper 2 in June 2022 and June 2023, plus the mark schemes examiners actually used to grade them. June 2019 is no longer published on Pearson's live archive, so we have not included it. Below is what real sub-questions on each recurring topic have asked, what a full mark answer looks like against that year's mark scheme, and what tripped candidates up.
Questions © Pearson Education Ltd, quoted for analysis. Diagrams, tables and apparatus described in our own words, not reproduced. Mark scheme content translated into plain English, not copied. PrepWise is independent and not endorsed by Pearson or Edexcel.
Every sitting we have gives you a balanced equation and a table of bond energies, then asks for the overall energy change with the correct sign.
You are given the bond energies for H-H, F-F and H-F and asked to work out the overall energy change for the reaction, including whether it is exothermic or endothermic.
A small table giving the bond energy in kJ per mole for the H-H bond, the F-F bond and the H-F bond, alongside the balanced equation H2 + F2 -> 2HF printed above the table.
| Bond | Bond energy (kJ/mol) |
|---|---|
| H-H | 436 |
| F-F | 158 |
| H-F | 562 |
Energy to break bonds in reactants = H-H + F-F = 436 + 158 = 594 kJ/mol. Energy released making bonds in products = 2 x H-F = 2 x 562 = 1124 kJ/mol. Overall energy change = 594 - 1124 = -530 kJ/mol. Since the value is negative, the reaction is exothermic.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise bond energy calculationsA small table giving the bond energy in kJ per mole for the triple bond in nitrogen, the H-H bond and the H-N bond, alongside the balanced equation for nitrogen reacting with hydrogen to form ammonia, N2 + 3H2 -> 2NH3, shown with a displayed structure of ammonia.
| Bond | Bond energy (kJ/mol) |
|---|---|
| N≡N (triple bond) | 944 |
| H-H | 436 |
| H-N | 388 |
Energy to break bonds in reactants = N-N triple bond + (3 x H-H) = 944 + (3 x 436) = 2252 kJ/mol. Energy released making bonds in products = 2 x (3 x H-N) = 2 x (3 x 388) = 2328 kJ/mol. Overall energy change = 2252 - 2328 = -76 kJ/mol.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise bond energy calculationsThe topic changes by sitting — the mark scheme never does. Learn this once, then open your question above for that sitting’s sources and a full worked answer.
Which statement correctly describes the energy change when chemical bonds are broken?
This calculation appears on every paper we analysed, always as a full multi-step calculation worth 4 marks. Learn the method (bonds broken minus bonds made) cold and always check your final sign.
Practise bond energy calculationsIn the sitting we have this question in, you are shown a reaction profile for an uncatalysed exothermic reaction and asked to discuss catalysts in general using named examples from the course.
This is question 9(b) on the June 2022 paper. It wants a general discussion of what catalysts do and why, backed up by named catalysed reactions from the specification, ideally shown on an amended or newly drawn reaction profile.
A reaction profile for an uncatalysed exothermic reaction, showing the energy axis against the progress of reaction, with the reactants starting at a lower energy level, a labelled peak in between, and the products ending at a lower energy level than the reactants.
A catalyst is a substance that increases the rate of a reaction without being used up or changing chemically itself, and without changing the products formed, so its own mass stays the same at the end of the reaction as at the start.
For a reaction to happen, particles must collide with at least a minimum amount of energy called the activation energy. A catalyst works by providing an alternative reaction pathway that has a lower activation energy than the uncatalysed route, so a greater proportion of collisions between particles have enough energy to be successful and go on to form products.
On the reaction profile in Figure 13, the catalysed version of this reaction would start and finish at exactly the same energy levels as the uncatalysed profile, since the reactants and products are chemically identical either way, but the new profile would show a lower peak in the middle, representing the lower activation energy of the catalysed pathway.
Two examples of catalysts I have met in chemistry are the iron catalyst used in the Haber process to make ammonia from nitrogen and hydrogen, and the enzymes contained in yeast that catalyse the fermentation of glucose to produce ethanol. Both increase the rate of their reaction without being consumed by it.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise reaction profile questionsThe topic changes by sitting — the mark scheme never does. Learn this once, then open your question above for that sitting’s sources and a full worked answer.
What does activation energy represent on a reaction profile?
This extended response wants named examples, not just a generic definition of a catalyst. Learn the Haber process, cracking and fermentation as your go-to catalysed reactions.
Practise reaction profile questionsBoth sittings we have give you a rate-of-reaction investigation with a metal or marble chips reacting with acid, then ask you to explain why the rate falls away over time in terms of particles being used up.
This is question 2(b)(ii) on the June 2023 paper. Using the gas volume against time data given, you need to explain why the reaction rate falls as marble chips react with hydrochloric acid, in terms of reactants being used up and collision frequency.
A table of the volume of gas produced each minute for six minutes as marble chips react with dilute hydrochloric acid.
| time in minutes | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
|---|---|---|---|---|---|---|---|
| volume of gas in cm3 | 0 | 52 | 78 | 91 | 97 | 100 | 100 |
A second table showing the rate of reaction calculated for each one-minute time interval from the Figure 4 results, which decreases steadily from the first interval to the last. The rate for the 2 to 3 minute interval is the value you are asked to calculate, so it is left blank here exactly as it is on the real exam paper.
| time interval | 0 to 1 minute | 1 to 2 minutes | 2 to 3 minutes | 3 to 4 minutes | 4 to 5 minutes |
|---|---|---|---|---|---|
| rate of reaction in cm3/min | 52 | 26 | ? | 6 | 3 |
The rate of reaction decreases as the reaction proceeds. This is because the reactants, the acid and the marble chips, are gradually used up as the reaction happens, so there are fewer acid particles and less marble chip surface available over time. With fewer reactant particles present, collisions between them become less frequent, so the rate of reaction falls.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise rate of reaction questionsA graph of the volume of hydrogen gas produced against time as metal pieces react with dilute hydrochloric acid, with the curve rising steeply at first and levelling off to a constant volume after about eight minutes.
The measurements could have been stopped at 9 minutes because the volume of gas had become constant, meaning the reaction had stopped producing any more hydrogen. This is shown on the graph by the curve levelling off (reaching zero gradient) rather than continuing to rise.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise rate of reaction questionsThe topic changes by sitting — the mark scheme never does. Learn this once, then open your question above for that sitting’s sources and a full worked answer.
Which of the following factors does NOT affect the rate of a chemical reaction?
This is really a collision theory question wearing a graph-reading disguise. Always link decreasing rate back to fewer particles colliding less often as reactants are used up.
Practise rate of reaction questionsIn the sitting we have this question in, you are shown a Bunsen burner and asked to link the air-hole setting to complete or incomplete combustion, and then to the harmful effects of burning large quantities of methane.
This is question 9(c) on the June 2023 paper. It wants you to connect the air-hole setting to complete versus incomplete combustion, name the different products in each case, and explain the harm both carbon monoxide and greenhouse gases can cause.
A diagram of a Bunsen burner, with the chimney and the air-hole on the chimney both labelled, showing where air enters to mix with the gas fuel before combustion.
When the air-hole is open, a large amount of oxygen can mix with the methane gas, so complete combustion takes place: CH4 + 2O2 -> CO2 + 2H2O. Only carbon dioxide and water are produced.
When the air-hole is closed, less oxygen is able to mix with the methane, so incomplete combustion takes place instead, for example 2CH4 + 3O2 -> 2CO + 4H2O. This time carbon monoxide is produced instead of carbon dioxide, and soot (carbon) can also form if there is very little oxygen available.
Carbon monoxide from incomplete combustion is harmful because it is a colourless and odourless gas, so people cannot detect it, and it combines with haemoglobin in red blood cells in place of oxygen, which reduces the blood's capacity to carry oxygen around the body and makes it toxic. Separately, both carbon dioxide and water vapour from complete combustion are greenhouse gases: they absorb heat energy radiated from the Earth's surface and re-radiate it, which increases the greenhouse effect, raises global temperatures, and contributes to climate change, including melting polar ice and rising sea levels.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise combustion questionsThe topic changes by sitting — the mark scheme never does. Learn this once, then open your question above for that sitting’s sources and a full worked answer.
What are the only products formed during the complete combustion of a hydrocarbon?
This question wants both combustion equations AND the harm they cause. Learn complete and incomplete combustion equations for methane cold, and know exactly why carbon monoxide is dangerous.
Practise combustion questionsIn the sitting we have this question in, you are shown a fractionating column and told the fractions get more viscous further down the column, then asked to explain why.
This is question 9(a)(ii) on the June 2023 paper. It wants an explanation linking the size of hydrocarbon molecules in each fraction to the strength of intermolecular forces and therefore viscosity.
A diagram of a fractionating column with crude oil entering at the bottom, and six labelled outlet pipes for gases, petrol, kerosene, diesel oil, fuel oil and bitumen going from top to bottom, alongside an arrow showing viscosity increases going down the column.
Viscosity increases down the column because the hydrocarbon molecules in each fraction get larger, containing more carbon atoms, the further down the column the fraction is collected. Larger molecules have stronger intermolecular forces of attraction between them, which makes the liquid flow less easily, so the fraction is more viscous.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise crude oil questionsThe topic changes by sitting — the mark scheme never does. Learn this once, then open your question above for that sitting’s sources and a full worked answer.
A hydrocarbon is a compound that contains only:
Trend questions like this always want the size-of-molecule link to intermolecular forces, not just a restated observation. Learn this two-step chain for viscosity and boiling point trends alike.
Practise crude oil questionsBoth sittings we have give you a displayed alkene structure and ask you to either complete an addition reaction with bromine or draw the polymer repeating unit it forms.
This is question 10(a)(ii) on the June 2022 paper. You need to add the formula for bromine and the correct product formula to complete the equation for the addition reaction of but-2-ene with bromine.
A displayed structural formula of but-2-ene, C4H8, showing a central C=C double bond with a CH3 group and an H atom attached to each of the two double-bonded carbons.
C4H8 + Br2 -> C4H8Br2. Bromine's formula, Br2, is added on the left, and the double bond in but-2-ene opens up so that one bromine atom attaches to each of the two carbons that were double bonded, giving C4H8Br2 as the single addition product.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise alkene and polymer questionsA table showing the displayed structures of propene, propanoic acid and ethanol side by side, with propene reacting with bromine water later in the same question, drawn as a displayed structural formula showing a C=C double bond with H atoms attached.
The product is 1,2-dibromopropane, drawn with a single bond between the three carbon atoms, a bromine atom attached to each of the first two carbons, and hydrogen atoms filling every other bond, since the C=C double bond in propene opens up to accept one bromine atom on each previously double-bonded carbon.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise alkene and polymer questionsThis is question 10(a)(iii) on the June 2022 paper. You need to draw the repeating unit of poly(but-2-ene), showing the double bond opened to a single bond with continuation bonds on either side.
The same displayed structural formula of but-2-ene, C4H8, used in the earlier part of the question, showing the C=C double bond with a CH3 group and an H atom on each double-bonded carbon.
The repeating unit shows two neighbouring carbon atoms joined by a single bond, each with a CH3 group and a hydrogen atom attached exactly as in the original but-2-ene structure, with continuation bonds extending outward from each carbon to show the unit repeats indefinitely, and crucially no C=C double bond remaining anywhere in the unit.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise alkene and polymer questionsA displayed structural formula of tetrafluoroethene, showing a C=C double bond with two fluorine atoms attached to each of the double-bonded carbons.
The repeating unit of poly(tetrafluoroethene) shows two carbon atoms joined by a single bond, each carbon carrying two fluorine atoms exactly as in the original tetrafluoroethene monomer, with continuation bonds shown on both ends of the unit and no C=C double bond present.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise alkene and polymer questionsThe topic changes by sitting — the mark scheme never does. Learn this once, then open your question above for that sitting’s sources and a full worked answer.
What is the general formula for alkenes?
Alkene structural questions always come down to one move: open the C=C double bond. Practise both the addition-reaction version and the polymer-repeating-unit version of this move.
Practise alkene and polymer questionsIn the sitting we have this question in, you are given the formula of glucose and asked to describe both the fermentation process and the fractional distillation process used to concentrate the ethanol produced.
This is question 7(b) on the June 2023 paper. It wants a full method for both fermenting glucose into dilute ethanol and then concentrating that ethanol using fractional distillation, in a clear logical order.
The question text itself, stating glucose is a carbohydrate with the formula C6H12O6, and that a dilute ethanol solution made by fermenting it is later processed to become more concentrated, with no additional diagram or apparatus provided.
To ferment the glucose, first dissolve the glucose in water to make a glucose solution, then place this solution into a suitable flask and add yeast. The flask is kept warm, at a temperature of around 25 to 35 degrees Celsius, since yeast enzymes work best in this range, and an air lock is fitted into the neck of the flask to let carbon dioxide escape while keeping oxygen out, since oxygen would allow the yeast to respire aerobically instead of fermenting the glucose anaerobically. The reaction is left until bubbles of carbon dioxide stop being produced, showing fermentation has finished, and then the dilute ethanol solution is decanted away from the solid yeast, or the yeast is filtered out.
To concentrate the dilute ethanol solution, fractional distillation is used. The dilute ethanol is placed in a round bottomed flask connected to a fractionating column, with a thermometer positioned at the top of the column, and the column is connected to a condenser with water running through its outer jacket. The flask is heated to a temperature above the boiling point of ethanol but below the boiling point of water, so mostly ethanol vapour rises up the fractionating column, is cooled and condensed back to a liquid in the condenser, and concentrated ethanol is collected as it drips out from the end of the condenser, leaving most of the water behind in the original flask.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise alcohol and fermentation questionsThe topic changes by sitting — the mark scheme never does. Learn this once, then open your question above for that sitting’s sources and a full worked answer.
What is the functional group present in all alcohols?
This question rewards a genuinely detailed method for at least one of the two processes, not a vague summary of both. Learn the air lock's purpose and the exact apparatus for fractional distillation.
Practise alcohol and fermentation questionsBoth sittings we have use a flame test, either asking you to identify unknown compounds from their flame colours or to spot and fix a flaw in the method that makes a conclusion invalid.
This is question 4(b)(ii) on the June 2022 paper. You are given the flame colours (red, lilac, blue-green) for three unknown compounds and need to name the correct metal ion for each based on standard flame test colours.
A small table listing three compounds, P, Q and R, alongside the flame colour observed for each: red for P, lilac for Q, and blue-green for R.
| Compound | Flame colour observed |
|---|---|
| P | red |
| Q | lilac |
| R | blue-green |
P contains lithium ions, since lithium compounds produce a red flame colour. Q contains potassium ions, since potassium compounds produce a lilac flame colour. R contains copper ions, since copper compounds produce a blue-green flame colour.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise flame test questionsThis is question 10(a)(i) on the June 2023 paper. You need to spot that the student's method (dipping a wooden splint into water then the solid, then into a Bunsen flame) risks contamination or an unreliable colour, and suggest a specific fix.
A student's stated method for a flame test on potassium chloride using a wooden splint dipped first in water, then in the solid sample, then held in a roaring Bunsen burner flame, alongside the student's observation of a yellow flame and their (incorrect) conclusion that this shows sodium ions.
The student should use a (nichrome) metal wire instead of a wooden splint, because a wooden splint itself burns in the flame, and the flame produced by the burning wood can interfere with or mask the true flame colour of the metal ions being tested, making the yellow colour unreliable evidence for sodium.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise flame test questionsThe topic changes by sitting — the mark scheme never does. Learn this once, then open your question above for that sitting’s sources and a full worked answer.
Which type of wire is used to carry out a flame test?
Flame test questions test two different skills: memorising the standard colours, and spotting practical flaws in a described method. Practise both versions.
Practise flame test questionsIn the sitting we have this question in, you are asked to describe the standard test for chloride ions, which uses acidified silver nitrate solution and a colour-coded precipitate.
This is question 10(b) on the June 2023 paper. It wants the full standard method for testing halide ions: acidifying with nitric acid, adding silver nitrate, and stating the correct precipitate colour for chloride specifically.
The question text stating a sample of potassium chloride, already used in the flame test earlier in the question, was also tested for chloride ions, with no additional apparatus diagram provided.
Add a few drops of dilute nitric acid to the sample of potassium chloride solution, then add silver nitrate solution. A white precipitate forms, which confirms the presence of chloride ions.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise ion test questionsThe topic changes by sitting — the mark scheme never does. Learn this once, then open your question above for that sitting’s sources and a full worked answer.
Which reagents are used to test for carbonate ions in a solution?
Ion test questions want the full sequence in order, not just the final colour. Learn nitric acid first, then silver nitrate, then the specific colour for each halide.
Practise ion test questionsIn the sitting we have this question in, you are asked to explain the full chain from a sulfur impurity in a fossil fuel to acid rain forming.
This is question 5(c) on the June 2023 paper. It wants the full chain of reasoning from a sulfur impurity in fossil fuel, through combustion to sulfur dioxide, to that gas dissolving in water to form acid rain.
The question text alone, stating that acid rain is caused by pollutant gases present in the atmosphere, with no additional diagram or data provided.
Some fossil fuels contain sulfur as an impurity. When the fuel is burned, this sulfur impurity is also burned, reacting with oxygen in the air to form sulfur dioxide gas. Sulfur dioxide then dissolves in water in rain or clouds, forming an acidic solution, which falls to the ground as acid rain.
Could you have written this? Every fact in this answer is drilled in our quizzes — the writing is the easy part once the evidence is automatic.
Practise atmospheric pollution questionsThe topic changes by sitting — the mark scheme never does. Learn this once, then open your question above for that sitting’s sources and a full worked answer.
Which of these gases is NOT a greenhouse gas?
This is a three-step chain question: name the impurity, explain the combustion reaction, then explain how the gas becomes acidic. Miss any one link and you lose a mark.
Practise atmospheric pollution questionsAcross the 2 sittings we have full papers for (June 2019 is no longer publicly available), these are the recurring question types and marks at stake on Paper 2.
The Haber process as a standalone extended response topic in these two papers · Chromatography and Rf value calculations as a standalone question in these two papers · Water treatment and life cycle assessment as standalone extended response topics in these two papers
These topics have not carried a full extended response question in the papers we analysed, but can still appear as shorter structured questions, so do not skip them entirely.
The data, tables and apparatus are described in our own words, not reproduced, and the worked answers are written entirely by us, aimed at the actual level descriptors and mark points of the real Edexcel mark schemes for each sitting. They are not copied from Edexcel's own exemplar materials, since that would breach copyright, but they are built to hit exactly what the real mark scheme rewarded that year. PrepWise is independent of Pearson and Edexcel and not endorsed by them.
We only build these pages from real past papers we can verify directly against Pearson's own published mark scheme. June 2019 is no longer available on Pearson's live public archive, so rather than guess at its content we have left it out entirely. We will add it if Pearson republishes it.
Bond energy calculations, rate of reaction explanations, flame tests and alkene structures return in some form in every single sitting we analysed, and the 6-mark extended response often falls on catalysts, combustion or fermentation. But you cannot rely on repeats alone, since the exact substance, numbers and context change every time even when the question type is similar. Use this page to see which QUESTION TYPES keep returning and make sure you know the underlying chemistry cold, whatever the exact wording turns out to be.
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