How Precipitate Formation Works
Part of Tests for Ions · GCSE GCSE Chemistry revision
This how it works covers How Precipitate Formation Works within Tests for Ions for GCSE Chemistry. Revise Tests for Ions in Chemical Analysis for GCSE Chemistry with 20 exam-style questions and 14 flashcards. This is a high-frequency topic, so it is worth revising until the explanation feels precise and repeatable. It is section 5 of 15 in this topic. Use this how it works to connect the idea to the wider topic before moving on to questions and flashcards.
Topic position
Section 5 of 15
Practice
20 questions
Recall
14 flashcards
⚙️ How Precipitate Formation Works
All these anion tests work through precipitation reactions — two soluble ionic compounds react to form one insoluble product (the precipitate) and one soluble product that stays in solution.
For the sulfate test with barium chloride: when BaCl₂(aq) and Na₂SO₄(aq) are mixed, the Ba²⁺ and SO₄²⁻ ions have an extremely strong attraction for each other. Barium sulfate is virtually insoluble in water — so as soon as Ba²⁺ meets SO₄²⁻, they combine and immediately drop out of solution as a solid. The Na⁺ and Cl⁻ ions are spectator ions — they remain dissolved and play no part in the reaction.
The net ionic equation (removing spectator ions) is: Ba²⁺(aq) + SO₄²⁻(aq) → BaSO₄(s)
For halide tests: silver ions have very different affinities for different halides. Ag⁺ + Cl⁻ gives a very insoluble white precipitate. Ag⁺ + Br⁻ gives a slightly less insoluble cream precipitate. Ag⁺ + I⁻ gives an even less insoluble yellow precipitate. The colours and solubilities are a direct result of the physical properties of the silver halide crystal structures.
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Practice Questions for Tests for Ions
Which reagents are used to test for carbonate ions in a solution?
Describe how sodium hydroxide solution can be used to distinguish between iron(II) ions and iron(III) ions in solution, including the expected observations.
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