This study notes covers Worked Examples within Area Under Curves for GCSE Mathematics. Revise Area Under Curves in Graphs for GCSE Mathematics with 9 exam-style questions and 10 flashcards. This topic appears regularly enough that it should still be part of a steady revision cycle. It is section 9 of 11 in this topic. Use this study notes to connect the idea to the wider topic before moving on to questions and flashcards.
Topic position
Section 9 of 11
Practice
9 questions
Recall
10 flashcards
✏️ Worked Examples
Example 1: Applying the Trapezium Rule
Question: Use the trapezium rule with 4 strips to estimate the area under a curve where the y-values at x = 0, 2, 4, 6, 8 are: y = 1, 4, 9, 7, 3. The strip width h = 2.
Show Solution
Step 1: Identify first, last, and middle y-values
First: y₀ = 1 Last: y₄ = 3 Middle: y₁ = 4, y₂ = 9, y₃ = 7
Step 2: Apply the trapezium rule formula
Area ≈ h/2 × (y₀ + 2y₁ + 2y₂ + 2y₃ + y₄)
Area ≈ 2/2 × (1 + 2(4) + 2(9) + 2(7) + 3)
Area ≈ 1 × (1 + 8 + 18 + 14 + 3)
Area ≈ 1 × 44 = 44 square units
Answer: Estimated area ≈ 44 square units
Example 2: Area Under a Speed-Time Graph
Question: A speed-time graph has 3 equal strips of width h = 5 seconds. The speed values at t = 0, 5, 10, 15 seconds are: 10, 14, 12, 8 m/s. Estimate the total distance travelled.
Show Solution
Step 1: Identify values — h = 5, y₀ = 10, y₁ = 14, y₂ = 12, y₃ = 8
Step 2: Apply the trapezium rule
Distance ≈ h/2 × (y₀ + 2y₁ + 2y₂ + y₃)
Distance ≈ 5/2 × (10 + 2(14) + 2(12) + 8)
Distance ≈ 2.5 × (10 + 28 + 24 + 8)
Distance ≈ 2.5 × 70 = 175 m
Interpretation: The object travels approximately 175 metres in 15 seconds.
Answer: Estimated distance ≈ 175 m